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7x+3-4x=3-3(x-4)
We move all terms to the left:
7x+3-4x-(3-3(x-4))=0
We add all the numbers together, and all the variables
3x-(3-3(x-4))+3=0
We calculate terms in parentheses: -(3-3(x-4)), so:We get rid of parentheses
3-3(x-4)
determiningTheFunctionDomain -3(x-4)+3
We multiply parentheses
-3x+12+3
We add all the numbers together, and all the variables
-3x+15
Back to the equation:
-(-3x+15)
3x+3x-15+3=0
We add all the numbers together, and all the variables
6x-12=0
We move all terms containing x to the left, all other terms to the right
6x=12
x=12/6
x=2
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