7x+3-3(-2x-3)=3(x-2)

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Solution for 7x+3-3(-2x-3)=3(x-2) equation: 



7x+3-3(-2x-3)=3(x-2)

We move all terms to the left:

7x+3-3(-2x-3)-(3(x-2))=0

We multiply parentheses

7x+6x-(3(x-2))+9+3=0



We calculate terms in parentheses: -(3(x-2)), so:

3(x-2)

We multiply parentheses

3x-6

Back to the equation:

-(3x-6)



We add all the numbers together, and all the variables

13x-(3x-6)+12=0

We get rid of parentheses

13x-3x+6+12=0

We add all the numbers together, and all the variables

10x+18=0

We move all terms containing x to the left, all other terms to the right

10x=-18

x=-18/10

x=-1+4/5

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