7x+3(4x-8)=108

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Solution for 7x+3(4x-8)=108 equation: 



7x+3(4x-8)=108

We move all terms to the left:

7x+3(4x-8)-(108)=0

We multiply parentheses

7x+12x-24-108=0

We add all the numbers together, and all the variables

19x-132=0

We move all terms containing x to the left, all other terms to the right

19x=132

x=132/19

x=6+18/19

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