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7x+3(2x-5)=5(2x-3)+3
We move all terms to the left:
7x+3(2x-5)-(5(2x-3)+3)=0
We multiply parentheses
7x+6x-(5(2x-3)+3)-15=0
We calculate terms in parentheses: -(5(2x-3)+3), so:We add all the numbers together, and all the variables
5(2x-3)+3
We multiply parentheses
10x-15+3
We add all the numbers together, and all the variables
10x-12
Back to the equation:
-(10x-12)
13x-(10x-12)-15=0
We get rid of parentheses
13x-10x+12-15=0
We add all the numbers together, and all the variables
3x-3=0
We move all terms containing x to the left, all other terms to the right
3x=3
x=3/3
x=1
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