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7x+3(2x+5)=5(2x+3)+2
We move all terms to the left:
7x+3(2x+5)-(5(2x+3)+2)=0
We multiply parentheses
7x+6x-(5(2x+3)+2)+15=0
We calculate terms in parentheses: -(5(2x+3)+2), so:We add all the numbers together, and all the variables
5(2x+3)+2
We multiply parentheses
10x+15+2
We add all the numbers together, and all the variables
10x+17
Back to the equation:
-(10x+17)
13x-(10x+17)+15=0
We get rid of parentheses
13x-10x-17+15=0
We add all the numbers together, and all the variables
3x-2=0
We move all terms containing x to the left, all other terms to the right
3x=2
x=2/3
x=2/3
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