7x+3((-3x-6)/10)=8

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Solution for 7x+3((-3x-6)/10)=8 equation: 



7x+3((-3x-6)/10)=8

We move all terms to the left:

7x+3((-3x-6)/10)-(8)=0

We multiply all the terms by the denominator


7x*10)+3((-3x-6)-8*10)=0

We add all the numbers together, and all the variables

7x*10)+3((-3x-6)=0

Wy multiply elements

70x^2=0

a = 70; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·70·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{140}=0$

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