7x+20=6(1+3x)-8

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Solution for 7x+20=6(1+3x)-8 equation: 



7x+20=6(1+3x)-8

We move all terms to the left:

7x+20-(6(1+3x)-8)=0

We add all the numbers together, and all the variables

7x-(6(3x+1)-8)+20=0



We calculate terms in parentheses: -(6(3x+1)-8), so:

6(3x+1)-8

We multiply parentheses

18x+6-8

We add all the numbers together, and all the variables

18x-2

Back to the equation:

-(18x-2)



We get rid of parentheses

7x-18x+2+20=0

We add all the numbers together, and all the variables

-11x+22=0

We move all terms containing x to the left, all other terms to the right

-11x=-22

x=-22/-11

x=+2

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