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7x+15-11=3(x+4)
We move all terms to the left:
7x+15-11-(3(x+4))=0
We add all the numbers together, and all the variables
7x-(3(x+4))+4=0
We calculate terms in parentheses: -(3(x+4)), so:We get rid of parentheses
3(x+4)
We multiply parentheses
3x+12
Back to the equation:
-(3x+12)
7x-3x-12+4=0
We add all the numbers together, and all the variables
4x-8=0
We move all terms containing x to the left, all other terms to the right
4x=8
x=8/4
x=2
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