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7x+12-3x=4(x+3)
We move all terms to the left:
7x+12-3x-(4(x+3))=0
We add all the numbers together, and all the variables
4x-(4(x+3))+12=0
We calculate terms in parentheses: -(4(x+3)), so:We get rid of parentheses
4(x+3)
We multiply parentheses
4x+12
Back to the equation:
-(4x+12)
4x-4x-12+12=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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