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7x*8x=100
We move all terms to the left:
7x*8x-(100)=0
Wy multiply elements
56x^2-100=0
a = 56; b = 0; c = -100;
Δ = b2-4ac
Δ = 02-4·56·(-100)
Δ = 22400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{22400}=\sqrt{1600*14}=\sqrt{1600}*\sqrt{14}=40\sqrt{14}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-40\sqrt{14}}{2*56}=\frac{0-40\sqrt{14}}{112} =-\frac{40\sqrt{14}}{112} =-\frac{5\sqrt{14}}{14} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+40\sqrt{14}}{2*56}=\frac{0+40\sqrt{14}}{112} =\frac{40\sqrt{14}}{112} =\frac{5\sqrt{14}}{14} $
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