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7x*3x=24
We move all terms to the left:
7x*3x-(24)=0
Wy multiply elements
21x^2-24=0
a = 21; b = 0; c = -24;
Δ = b2-4ac
Δ = 02-4·21·(-24)
Δ = 2016
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2016}=\sqrt{144*14}=\sqrt{144}*\sqrt{14}=12\sqrt{14}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{14}}{2*21}=\frac{0-12\sqrt{14}}{42} =-\frac{12\sqrt{14}}{42} =-\frac{2\sqrt{14}}{7} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{14}}{2*21}=\frac{0+12\sqrt{14}}{42} =\frac{12\sqrt{14}}{42} =\frac{2\sqrt{14}}{7} $
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