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7x(x+2)=7
We move all terms to the left:
7x(x+2)-(7)=0
We multiply parentheses
7x^2+14x-7=0
a = 7; b = 14; c = -7;
Δ = b2-4ac
Δ = 142-4·7·(-7)
Δ = 392
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{392}=\sqrt{196*2}=\sqrt{196}*\sqrt{2}=14\sqrt{2}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-14\sqrt{2}}{2*7}=\frac{-14-14\sqrt{2}}{14} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+14\sqrt{2}}{2*7}=\frac{-14+14\sqrt{2}}{14} $
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