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7x(x+3)=70
We move all terms to the left:
7x(x+3)-(70)=0
We multiply parentheses
7x^2+21x-70=0
a = 7; b = 21; c = -70;
Δ = b2-4ac
Δ = 212-4·7·(-70)
Δ = 2401
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2401}=49$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(21)-49}{2*7}=\frac{-70}{14} =-5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(21)+49}{2*7}=\frac{28}{14} =2 $
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