7x(7x+20)=629

Solution for 7x(7x+20)=629 equation:

7x(7x+20)=629

We move all terms to the left:

7x(7x+20)-(629)=0

We multiply parentheses

49x^2+140x-629=0

a = 49; b = 140; c = -629;
Δ = b2-4ac
Δ = 1402-4·49·(-629)
Δ = 142884
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{142884}=378$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(140)-378}{2*49}=\frac{-518}{98}
=-5+2/7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(140)+378}{2*49}=\frac{238}{98}
=2+3/7
$