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7x(4+2x)-4x=16+7x
We move all terms to the left:
7x(4+2x)-4x-(16+7x)=0
We add all the numbers together, and all the variables
7x(2x+4)-4x-(7x+16)=0
We add all the numbers together, and all the variables
-4x+7x(2x+4)-(7x+16)=0
We multiply parentheses
14x^2-4x+28x-(7x+16)=0
We get rid of parentheses
14x^2-4x+28x-7x-16=0
We add all the numbers together, and all the variables
14x^2+17x-16=0
a = 14; b = 17; c = -16;
Δ = b2-4ac
Δ = 172-4·14·(-16)
Δ = 1185
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-\sqrt{1185}}{2*14}=\frac{-17-\sqrt{1185}}{28} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+\sqrt{1185}}{2*14}=\frac{-17+\sqrt{1185}}{28} $
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