7x(3x-2)-6x+4=-

Solution for 7x(3x-2)-6x+4=- equation:

7x(3x-2)-6x+4=-

We move all terms to the left:

7x(3x-2)-6x+4-(-)=0

We add all the numbers together, and all the variables

7x(3x-2)-6x+4-0=0

We add all the numbers together, and all the variables

-6x+7x(3x-2)+4=0

We multiply parentheses

21x^2-6x-14x+4=0

We add all the numbers together, and all the variables

21x^2-20x+4=0

a = 21; b = -20; c = +4;
Δ = b2-4ac
Δ = -202-4·21·4
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-8}{2*21}=\frac{12}{42}
=2/7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+8}{2*21}=\frac{28}{42}
=2/3
$