7w-3(w+2)=w+5(w-1)

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Solution for 7w-3(w+2)=w+5(w-1) equation: 



7w-3(w+2)=w+5(w-1)

We move all terms to the left:

7w-3(w+2)-(w+5(w-1))=0

We multiply parentheses

7w-3w-(w+5(w-1))-6=0



We calculate terms in parentheses: -(w+5(w-1)), so:

w+5(w-1)

We multiply parentheses

w+5w-5

We add all the numbers together, and all the variables

6w-5

Back to the equation:

-(6w-5)



We add all the numbers together, and all the variables

4w-(6w-5)-6=0

We get rid of parentheses

4w-6w+5-6=0

We add all the numbers together, and all the variables

-2w-1=0

We move all terms containing w to the left, all other terms to the right

-2w=1

w=1/-2

w=-1/2

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