7v2+37v+10=0

Solution for 7v2+37v+10=0 equation:

7v^2+37v+10=0

a = 7; b = 37; c = +10;
Δ = b2-4ac
Δ = 372-4·7·10
Δ = 1089
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1089}=33$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(37)-33}{2*7}=\frac{-70}{14}
=-5
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(37)+33}{2*7}=\frac{-4}{14}
=-2/7
$