7v-8+3(3v+1)=-2(v+4)

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Solution for 7v-8+3(3v+1)=-2(v+4) equation: 



7v-8+3(3v+1)=-2(v+4)

We move all terms to the left:

7v-8+3(3v+1)-(-2(v+4))=0

We multiply parentheses

7v+9v-(-2(v+4))+3-8=0



We calculate terms in parentheses: -(-2(v+4)), so:

-2(v+4)

We multiply parentheses

-2v-8

Back to the equation:

-(-2v-8)



We add all the numbers together, and all the variables

16v-(-2v-8)-5=0

We get rid of parentheses

16v+2v+8-5=0

We add all the numbers together, and all the variables

18v+3=0

We move all terms containing v to the left, all other terms to the right

18v=-3

v=-3/18

v=-1/6

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