7v+35=3(v+1)

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Solution for 7v+35=3(v+1) equation: 



7v+35=3(v+1)

We move all terms to the left:

7v+35-(3(v+1))=0



We calculate terms in parentheses: -(3(v+1)), so:

3(v+1)

We multiply parentheses

3v+3

Back to the equation:

-(3v+3)



We get rid of parentheses

7v-3v-3+35=0

We add all the numbers together, and all the variables

4v+32=0

We move all terms containing v to the left, all other terms to the right

4v=-32

v=-32/4

v=-8

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