7v+32=2(v-9)

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Solution for 7v+32=2(v-9) equation: 



7v+32=2(v-9)

We move all terms to the left:

7v+32-(2(v-9))=0



We calculate terms in parentheses: -(2(v-9)), so:

2(v-9)

We multiply parentheses

2v-18

Back to the equation:

-(2v-18)



We get rid of parentheses

7v-2v+18+32=0

We add all the numbers together, and all the variables

5v+50=0

We move all terms containing v to the left, all other terms to the right

5v=-50

v=-50/5

v=-10

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