7v+22=4(v-2)

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Solution for 7v+22=4(v-2) equation:



7v+22=4(v-2)
We move all terms to the left:
7v+22-(4(v-2))=0
We calculate terms in parentheses: -(4(v-2)), so:
4(v-2)
We multiply parentheses
4v-8
Back to the equation:
-(4v-8)
We get rid of parentheses
7v-4v+8+22=0
We add all the numbers together, and all the variables
3v+30=0
We move all terms containing v to the left, all other terms to the right
3v=-30
v=-30/3
v=-10

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