7u2+u-5=0

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Solution for 7u2+u-5=0 equation: 



7u^2+u-5=0

a = 7; b = 1; c = -5;
Δ = b2-4ac
Δ = 12-4·7·(-5)
Δ = 141
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{141}}{2*7}=\frac{-1-\sqrt{141}}{14}
$


$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{141}}{2*7}=\frac{-1+\sqrt{141}}{14}
$

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