7u-6+2(4u+5)=-3(u+2)

Solution for 7u-6+2(4u+5)=-3(u+2) equation:

7u-6+2(4u+5)=-3(u+2)

We move all terms to the left:

7u-6+2(4u+5)-(-3(u+2))=0

We multiply parentheses

7u+8u-(-3(u+2))+10-6=0


We calculate terms in parentheses: -(-3(u+2)), so:

-3(u+2)

We multiply parentheses

-3u-6

Back to the equation:

-(-3u-6)


We add all the numbers together, and all the variables

15u-(-3u-6)+4=0

We get rid of parentheses

15u+3u+6+4=0

We add all the numbers together, and all the variables

18u+10=0

We move all terms containing u to the left, all other terms to the right

18u=-10

u=-10/18

u=-5/9