7u+5-3(-2u-2)=3(u-1)

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Solution for 7u+5-3(-2u-2)=3(u-1) equation: 



7u+5-3(-2u-2)=3(u-1)

We move all terms to the left:

7u+5-3(-2u-2)-(3(u-1))=0

We multiply parentheses

7u+6u-(3(u-1))+6+5=0



We calculate terms in parentheses: -(3(u-1)), so:

3(u-1)

We multiply parentheses

3u-3

Back to the equation:

-(3u-3)



We add all the numbers together, and all the variables

13u-(3u-3)+11=0

We get rid of parentheses

13u-3u+3+11=0

We add all the numbers together, and all the variables

10u+14=0

We move all terms containing u to the left, all other terms to the right

10u=-14

u=-14/10

u=-1+2/5

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