7u+12=3(u-4)

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Solution for 7u+12=3(u-4) equation: 



7u+12=3(u-4)

We move all terms to the left:

7u+12-(3(u-4))=0



We calculate terms in parentheses: -(3(u-4)), so:

3(u-4)

We multiply parentheses

3u-12

Back to the equation:

-(3u-12)



We get rid of parentheses

7u-3u+12+12=0

We add all the numbers together, and all the variables

4u+24=0

We move all terms containing u to the left, all other terms to the right

4u=-24

u=-24/4

u=-6

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