7t+5(4+t)=24+5(2+t)

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Solution for 7t+5(4+t)=24+5(2+t) equation: 



7t+5(4+t)=24+5(2+t)

We move all terms to the left:

7t+5(4+t)-(24+5(2+t))=0

We add all the numbers together, and all the variables

7t+5(t+4)-(24+5(t+2))=0

We multiply parentheses

7t+5t-(24+5(t+2))+20=0



We calculate terms in parentheses: -(24+5(t+2)), so:

24+5(t+2)

determiningTheFunctionDomain
5(t+2)+24

We multiply parentheses

5t+10+24

We add all the numbers together, and all the variables

5t+34

Back to the equation:

-(5t+34)



We add all the numbers together, and all the variables

12t-(5t+34)+20=0

We get rid of parentheses

12t-5t-34+20=0

We add all the numbers together, and all the variables

7t-14=0

We move all terms containing t to the left, all other terms to the right

7t=14

t=14/7

t=2

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