7t+2t2=5

Solution for 7t+2t2=5 equation:

7t+2t^2=5

We move all terms to the left:

7t+2t^2-(5)=0

a = 2; b = 7; c = -5;
Δ = b2-4ac
Δ = 72-4·2·(-5)
Δ = 89
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{89}}{2*2}=\frac{-7-\sqrt{89}}{4}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{89}}{2*2}=\frac{-7+\sqrt{89}}{4}
$