7s-(3s+4)=4(3+2s)

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Solution for 7s-(3s+4)=4(3+2s) equation: 



7s-(3s+4)=4(3+2s)

We move all terms to the left:

7s-(3s+4)-(4(3+2s))=0

We add all the numbers together, and all the variables

7s-(3s+4)-(4(2s+3))=0

We get rid of parentheses

7s-3s-(4(2s+3))-4=0



We calculate terms in parentheses: -(4(2s+3)), so:

4(2s+3)

We multiply parentheses

8s+12

Back to the equation:

-(8s+12)



We add all the numbers together, and all the variables

4s-(8s+12)-4=0

We get rid of parentheses

4s-8s-12-4=0

We add all the numbers together, and all the variables

-4s-16=0

We move all terms containing s to the left, all other terms to the right

-4s=16

s=16/-4

s=-4

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