7q=(-6)+10q

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Solution for 7q=(-6)+10q equation: 



7q=(-6)+10q

We move all terms to the left:

7q-((-6)+10q)=0



We calculate terms in parentheses: -((-6)+10q), so:

(-6)+10q

determiningTheFunctionDomain
10q+(-6)

We add all the numbers together, and all the variables

10q-6

Back to the equation:

-(10q-6)



We get rid of parentheses

7q-10q+6=0

We add all the numbers together, and all the variables

-3q+6=0

We move all terms containing q to the left, all other terms to the right

-3q=-6

q=-6/-3

q=+2

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