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7p^2+7p-42=0
a = 7; b = 7; c = -42;
Δ = b2-4ac
Δ = 72-4·7·(-42)
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1225}=35$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-35}{2*7}=\frac{-42}{14} =-3 $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+35}{2*7}=\frac{28}{14} =2 $
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