7p-3(6-5p)=3(p-6)-35

Solution for 7p-3(6-5p)=3(p-6)-35 equation:

7p-3(6-5p)=3(p-6)-35

We move all terms to the left:

7p-3(6-5p)-(3(p-6)-35)=0

We add all the numbers together, and all the variables

7p-3(-5p+6)-(3(p-6)-35)=0

We multiply parentheses

7p+15p-(3(p-6)-35)-18=0


We calculate terms in parentheses: -(3(p-6)-35), so:

3(p-6)-35

We multiply parentheses

3p-18-35

We add all the numbers together, and all the variables

3p-53

Back to the equation:

-(3p-53)


We add all the numbers together, and all the variables

22p-(3p-53)-18=0

We get rid of parentheses

22p-3p+53-18=0

We add all the numbers together, and all the variables

19p+35=0

We move all terms containing p to the left, all other terms to the right

19p=-35

p=-35/19

p=-1+16/19