7p+(1-p)=1p+9(1-p)

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Solution for 7p+(1-p)=1p+9(1-p) equation: 



7p+(1-p)=1p+9(1-p)

We move all terms to the left:

7p+(1-p)-(1p+9(1-p))=0

We add all the numbers together, and all the variables

7p+(-1p+1)-(1p+9(-1p+1))=0

We get rid of parentheses

7p-1p-(1p+9(-1p+1))+1=0



We calculate terms in parentheses: -(1p+9(-1p+1)), so:

1p+9(-1p+1)

We add all the numbers together, and all the variables

p+9(-1p+1)

We multiply parentheses

p-9p+9

We add all the numbers together, and all the variables

-8p+9

Back to the equation:

-(-8p+9)



We add all the numbers together, and all the variables

6p-(-8p+9)+1=0

We get rid of parentheses

6p+8p-9+1=0

We add all the numbers together, and all the variables

14p-8=0

We move all terms containing p to the left, all other terms to the right

14p=8

p=8/14

p=4/7

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