7n2+-43n+6=0

Solution for 7n2+-43n+6=0 equation:

7n^2+-43n+6=0

We add all the numbers together, and all the variables

7n^2-43n=0

a = 7; b = -43; c = 0;
Δ = b2-4ac
Δ = -432-4·7·0
Δ = 1849
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1849}=43$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-43)-43}{2*7}=\frac{0}{14}
=0
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-43)+43}{2*7}=\frac{86}{14}
=6+1/7
$