7n-5(n-5)=4n+29

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Solution for 7n-5(n-5)=4n+29 equation: 



7n-5(n-5)=4n+29

We move all terms to the left:

7n-5(n-5)-(4n+29)=0

We multiply parentheses

7n-5n-(4n+29)+25=0

We get rid of parentheses

7n-5n-4n-29+25=0

We add all the numbers together, and all the variables

-2n-4=0

We move all terms containing n to the left, all other terms to the right

-2n=4

n=4/-2

n=-2

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