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7m=9(m/4)
We move all terms to the left:
7m-(9(m/4))=0
We add all the numbers together, and all the variables
7m-(9(+m/4))=0
We multiply all the terms by the denominator
7m*4))-(9(+m=0
We add all the numbers together, and all the variables
m+7m*4))-(9(=0
Wy multiply elements
28m^2+m=0
a = 28; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·28·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*28}=\frac{-2}{56} =-1/28 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*28}=\frac{0}{56} =0 $
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