7m+4(m+3)=5m+6(2m-1)

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Solution for 7m+4(m+3)=5m+6(2m-1) equation: 



7m+4(m+3)=5m+6(2m-1)

We move all terms to the left:

7m+4(m+3)-(5m+6(2m-1))=0

We multiply parentheses

7m+4m-(5m+6(2m-1))+12=0



We calculate terms in parentheses: -(5m+6(2m-1)), so:

5m+6(2m-1)

We multiply parentheses

5m+12m-6

We add all the numbers together, and all the variables

17m-6

Back to the equation:

-(17m-6)



We add all the numbers together, and all the variables

11m-(17m-6)+12=0

We get rid of parentheses

11m-17m+6+12=0

We add all the numbers together, and all the variables

-6m+18=0

We move all terms containing m to the left, all other terms to the right

-6m=-18

m=-18/-6

m=+3

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