7k-35=(1+2k)+2k

Solution for 7k-35=(1+2k)+2k equation:

7k-35=(1+2k)+2k

We move all terms to the left:

7k-35-((1+2k)+2k)=0

We add all the numbers together, and all the variables

7k-((2k+1)+2k)-35=0


We calculate terms in parentheses: -((2k+1)+2k), so:

(2k+1)+2k

We add all the numbers together, and all the variables

2k+(2k+1)

We get rid of parentheses

2k+2k+1

We add all the numbers together, and all the variables

4k+1

Back to the equation:

-(4k+1)


We get rid of parentheses

7k-4k-1-35=0

We add all the numbers together, and all the variables

3k-36=0

We move all terms containing k to the left, all other terms to the right

3k=36

k=36/3

k=12