7k-2(2k-1)=4(k-3)=

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Solution for 7k-2(2k-1)=4(k-3)= equation: 



7k-2(2k-1)=4(k-3)=

We move all terms to the left:

7k-2(2k-1)-(4(k-3))=0

We multiply parentheses

7k-4k-(4(k-3))+2=0



We calculate terms in parentheses: -(4(k-3)), so:

4(k-3)

We multiply parentheses

4k-12

Back to the equation:

-(4k-12)



We add all the numbers together, and all the variables

3k-(4k-12)+2=0

We get rid of parentheses

3k-4k+12+2=0

We add all the numbers together, and all the variables

-1k+14=0

We move all terms containing k to the left, all other terms to the right

-k=-14

k=-14/-1

k=+14

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