7k+19=4(k+5)+3k-1

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Solution for 7k+19=4(k+5)+3k-1 equation: 



7k+19=4(k+5)+3k-1

We move all terms to the left:

7k+19-(4(k+5)+3k-1)=0



We calculate terms in parentheses: -(4(k+5)+3k-1), so:

4(k+5)+3k-1

We add all the numbers together, and all the variables

3k+4(k+5)-1

We multiply parentheses

3k+4k+20-1

We add all the numbers together, and all the variables

7k+19

Back to the equation:

-(7k+19)



We get rid of parentheses

7k-7k-19+19=0

We add all the numbers together, and all the variables

=0

k=0/1

k=0

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