7h=-(2h-18)7h=-(2h-18)

Solution for 7h=-(2h-18)7h=-(2h-18) equation:

7h=-(2h-18)7h=-(2h-18)

We move all terms to the left:

7h-(-(2h-18)7h)=0


We calculate terms in parentheses: -(-(2h-18)7h), so:

-(2h-18)7h

We multiply parentheses

-14h^2+126h

Back to the equation:

-(-14h^2+126h)


We get rid of parentheses

14h^2-126h+7h=0

We add all the numbers together, and all the variables

14h^2-119h=0

a = 14; b = -119; c = 0;
Δ = b2-4ac
Δ = -1192-4·14·0
Δ = 14161
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{14161}=119$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-119)-119}{2*14}=\frac{0}{28}
=0
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-119)+119}{2*14}=\frac{238}{28}
=8+1/2
$