7h(h-3)=33

Solution for 7h(h-3)=33 equation:

7h(h-3)=33

We move all terms to the left:

7h(h-3)-(33)=0

We multiply parentheses

7h^2-21h-33=0

a = 7; b = -21; c = -33;
Δ = b2-4ac
Δ = -212-4·7·(-33)
Δ = 1365
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-21)-\sqrt{1365}}{2*7}=\frac{21-\sqrt{1365}}{14}
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-21)+\sqrt{1365}}{2*7}=\frac{21+\sqrt{1365}}{14}
$