7f=(-3f-10)/5

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Solution for 7f=(-3f-10)/5 equation: 



7f=(-3f-10)/5

We move all terms to the left:

7f-((-3f-10)/5)=0

We multiply all the terms by the denominator


7f*5)-((-3f-10)=0

Wy multiply elements

35f^2=0

a = 35; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·35·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$f=\frac{-b}{2a}=\frac{0}{70}=0$

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