7f+3(3+f)=-28+2f-6

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Solution for 7f+3(3+f)=-28+2f-6 equation: 



7f+3(3+f)=-28+2f-6

We move all terms to the left:

7f+3(3+f)-(-28+2f-6)=0

We add all the numbers together, and all the variables

7f+3(f+3)-(2f-34)=0

We multiply parentheses

7f+3f-(2f-34)+9=0

We get rid of parentheses

7f+3f-2f+34+9=0

We add all the numbers together, and all the variables

8f+43=0

We move all terms containing f to the left, all other terms to the right

8f=-43

f=-43/8

f=-5+3/8

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