7c-4(c+4)=4(3-c)

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Solution for 7c-4(c+4)=4(3-c) equation: 



7c-4(c+4)=4(3-c)

We move all terms to the left:

7c-4(c+4)-(4(3-c))=0

We add all the numbers together, and all the variables

7c-4(c+4)-(4(-1c+3))=0

We multiply parentheses

7c-4c-(4(-1c+3))-16=0



We calculate terms in parentheses: -(4(-1c+3)), so:

4(-1c+3)

We multiply parentheses

-4c+12

Back to the equation:

-(-4c+12)



We add all the numbers together, and all the variables

3c-(-4c+12)-16=0

We get rid of parentheses

3c+4c-12-16=0

We add all the numbers together, and all the variables

7c-28=0

We move all terms containing c to the left, all other terms to the right

7c=28

c=28/7

c=4

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