7c-4(c+4)=(3-c)

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Solution for 7c-4(c+4)=(3-c) equation: 



7c-4(c+4)=(3-c)

We move all terms to the left:

7c-4(c+4)-((3-c))=0

We add all the numbers together, and all the variables

7c-4(c+4)-((-1c+3))=0

We multiply parentheses

7c-4c-((-1c+3))-16=0



We calculate terms in parentheses: -((-1c+3)), so:

(-1c+3)

We get rid of parentheses

-1c+3

Back to the equation:

-(-1c+3)



We add all the numbers together, and all the variables

3c-(-1c+3)-16=0

We get rid of parentheses

3c+1c-3-16=0

We add all the numbers together, and all the variables

4c-19=0

We move all terms containing c to the left, all other terms to the right

4c=19

c=19/4

c=4+3/4

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