7c-2(3c+1)=5(4-2c)

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Solution for 7c-2(3c+1)=5(4-2c) equation:


Simplifying
7c + -2(3c + 1) = 5(4 + -2c)

Reorder the terms:
7c + -2(1 + 3c) = 5(4 + -2c)
7c + (1 * -2 + 3c * -2) = 5(4 + -2c)
7c + (-2 + -6c) = 5(4 + -2c)

Reorder the terms:
-2 + 7c + -6c = 5(4 + -2c)

Combine like terms: 7c + -6c = 1c
-2 + 1c = 5(4 + -2c)
-2 + 1c = (4 * 5 + -2c * 5)
-2 + 1c = (20 + -10c)

Solving
-2 + 1c = 20 + -10c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '10c' to each side of the equation.
-2 + 1c + 10c = 20 + -10c + 10c

Combine like terms: 1c + 10c = 11c
-2 + 11c = 20 + -10c + 10c

Combine like terms: -10c + 10c = 0
-2 + 11c = 20 + 0
-2 + 11c = 20

Add '2' to each side of the equation.
-2 + 2 + 11c = 20 + 2

Combine like terms: -2 + 2 = 0
0 + 11c = 20 + 2
11c = 20 + 2

Combine like terms: 20 + 2 = 22
11c = 22

Divide each side by '11'.
c = 2

Simplifying
c = 2

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