7c+3=6(c-4)-2c

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Solution for 7c+3=6(c-4)-2c equation: 



7c+3=6(c-4)-2c

We move all terms to the left:

7c+3-(6(c-4)-2c)=0



We calculate terms in parentheses: -(6(c-4)-2c), so:

6(c-4)-2c

We add all the numbers together, and all the variables

-2c+6(c-4)

We multiply parentheses

-2c+6c-24

We add all the numbers together, and all the variables

4c-24

Back to the equation:

-(4c-24)



We get rid of parentheses

7c-4c+24+3=0

We add all the numbers together, and all the variables

3c+27=0

We move all terms containing c to the left, all other terms to the right

3c=-27

c=-27/3

c=-9

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