7c+2=4(c+5)+3(c-6)

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Solution for 7c+2=4(c+5)+3(c-6) equation: 



7c+2=4(c+5)+3(c-6)

We move all terms to the left:

7c+2-(4(c+5)+3(c-6))=0



We calculate terms in parentheses: -(4(c+5)+3(c-6)), so:

4(c+5)+3(c-6)

We multiply parentheses

4c+3c+20-18

We add all the numbers together, and all the variables

7c+2

Back to the equation:

-(7c+2)



We get rid of parentheses

7c-7c-2+2=0

We add all the numbers together, and all the variables

=0

c=0/1

c=0

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