7c+12=4c+18

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Solution for 7c+12=4c+18 equation: 



7c+12=4c+18

We move all terms to the left:

7c+12-(4c+18)=0

We get rid of parentheses

7c-4c-18+12=0

We add all the numbers together, and all the variables

3c-6=0

We move all terms containing c to the left, all other terms to the right

3c=6

c=6/3

c=2

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